Convert from lambda to def

Given a piece of code with a function assigned by lambda, rewrite it into a function assigned by def. The code given would be in string.

Overview

This is a quick example of a lambda expression:

func = lambda a, b: a * (b - 2)

... is the same as ...

def func(a, b):
  return a * (b - 2)

Examples

lambda_to_def("func = lambda w: w + 'lambda'") ➞ "def func(w):\n\treturn w + 'lambda'"

lambda_to_def("z = lambda lambdadef: lambdadef.split(':')") ➞ "def z(lambdadef):\n\treturn lambdadef.split(':')"

Visualisation:

print(lambda_to_def("func = lambda w: w + 'lambda'"))

def func(w):
  return w + 'lambda'

print(lambda_to_def("z = lambda lambdadef: lambdadef.split(':')"))

def z(lambdadef):
  return lambdadef.split(':')

Notes

• The new code should follow PEP8 guidelines.
• For the sake of convenience, use \t for indentation.
• Assume all lambda expressions are valid.