The function is given a string representing a linear equation with one unknown. Find the value of x that is a valid solution of the equation. Return the sting x=val. Three outcomes are possible:
x_val is an integer or a float (round x_val to 2 decimals)"Infinite solutions" for situations 0*x=0"No solution" for situations 0*x=num, (num != 0)findX("4x-7=x+11") ➞ "x=6"
findX("3x=2x+x") ➞ "Infinite solutions"
findX("3x=3x+2") ➞ "No solution"
findX("-1-2x=15+x") ➞ "x=-5.33"